Chapter-7|Alternating Current |NCERT 12th Physics:
AC Voltage Applied to an Inductor:
Let an inductor with self inductance(L) is connected to an AC source with instantaneous EMF (V) which is given by
V= V₀Sinωt
Applying Kirchhoff’s law, Net potential across the circuit will be zero
= ωt-(ωt-π/2) = π/2