Ncert 12th Physics Chapter-1

Application of gauss theorem 2

Applications of Gauss’ Theorem(Field Due to a Uniformly Charged Thin Spherical Shell)

Chapter-1|Electric Charges and Fields | NCERT 12th Physics: (III) Field Due to a Uniformly Charged Thin Spherical Shell: Let σ be the uniform surface charge density of a thin spherical shell of radius R. The Gaussion surface will be a spherical surface centred at the centre of shell.   (a) At a point outside the […]

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Application of gauss theorem 1

Applications of Gauss’ Theorem( Field Due to Thin Infinite Plane Sheet of Charge)

Chapter-1|Electric Charges and Fields | NCERT 12th Physics: Applications of Gauss’ Theorem: (II)Field Due to Thin Infinite Plane Sheet of Charge: We consider a thin, infinite plane sheet of charge with uniform surface charge density Sigma(σ).We want to calculate its electric field at point P, at distance r from it. Now, to form a Gaussian

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Application of gauss theorem

Applications of Gauss’ Theorem(Field Due to an Infinitely long Charged Wire)

Chapter-1|Electric Charges and Fields | NCERT 12th Physics: Applications of Gauss’ Theorem: (I) Field Due to an Infinitely long Charged Wire: We consider a thin infinitely long straight wire having a uniform linear density λ. To determine the field at a distance r from the line charge, we choose a cylindrical Gaussion surface of radius r, length

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Gauss theorem

Gauss’ Theorem

Chapter-1|Electric Charges and Fields | NCERT 12th Physics: Gauss’ Theorem: This theorem gives a relationship between the total flux passing through any closed surface and the net charge enclosed within the surface. ”Gauss’ theorem state that the total flux through any closed surface is 1/ε₀ times the net charge enclosed by the closed surface”. Mathematically, it

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Electric flux

Electric Flux

Chapter-1|Electric Charges and Fields | NCERT 12th Physics: Electric Flux: Electric flux linked with any surface is defined as the total number of electric field lines that normally passes through that surface. It is represented by ØE. Electric flux depends upon three factors. (I)   Area(A) (II)  Strength of electric field. (III)  Angle between area vector and

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Area vector

Area Vector

Chapter-1|Electric Charges and Fields | NCERT 12th Physics: Area Vector: The vector associated with every area element of a closed surface is taken to be in the direction of the outward normal. Thus the area element vector ∆S at a point on a closed surface is equal to ∆Sn∧, where ∆S is magnitude of area

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